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I have a rectangular grid of points like this and I want to get indices of these points which forms a hexagonal grid like this .
How can I "Hexagonalize" the rectangular grid given that I want to draw only complete hexagons? Also, I can't offset the co-ordinates, I generate these co-ordinates in a procedural way.
Precisely, all I need is the indices for the hexagonal-grid in the array, I have (x,y,z) cooridnates for each of these indices which I will use later. From your comment, it appears that the numbers aren't assigned to the squares, they're assigned to the line immediately below or to their left (and that you listed the y-coordinate first).


So you are basically asking me to do this: for(x= 0 to n){ for(y=0 to n){ new[x,y] = old[xmod2, ymod4]}} ? Not the answer you're looking for?Browse other questions tagged c++ math geometry or ask your own question. How do I rotate hexagon points I've generated or generate it so that the first point is center-top? If I have a line from point x1, y1 to x2, y2, how can I draw 2 lines coming from point x2, y2 at 45 degree angles to make an arrow?
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Or are you trying to represent your hexagonal grid with a rectangular such that you are able to determine adjacency?
If the index called is odd, you go to the inner cells in your drawing with length N-1, otherwise the outer ones with length N. So, in your hexagonal grid picture, all the rows that have 16 elements can be taken into one rectangular array of size 16x16 (those are the rows that have even indices), and all the other rows that have 15 elements can be taken as another grid with size 15x15. If what you want to do is a hexagonal array that you can store data in it, then my way is the way to go. But, I don't need the connections, all I need to know is which indices of the rectangular grid make it into the hexagonal grid. If you're talking about Geometry (which I find from your last edit), then maybe you just have to ignore my answer.



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