# Napkin Problem 2: Expected Database Query Latency

Fellow computer-napkin-mathers, it's time for napkin problem #2. The last problem's solution you'll find at the end! I've updated sirupsen/napkin-math with last week's tips and tricks--consult that repo if you need a refresher. My goal for that repo is to become a great resource for napkin calculations in the domain of computers. My talk from SRECON's video was published this week, you can see it here.

**Problem #2: Your SSD-backed database has a usage-pattern that rewards you with
a 80% page-cache hit-rate (i.e. 80% of disk reads are served directly out of
memory instead of going to the SSD). The median is 50 distinct disk pages for a
query to gather its query results (e.g. InnoDB pages in MySQL). What is the
expected average query time from your database?**

Reply to this email with your answer, happy to provide you mine ahead of time if you're curious.

*Solution to this problem is available in the next edition*

**Last Problem's Solution**

**Question:** **How much will the storage of logs cost for a standard,
monolithic 100,000 RPS web application?**

**Answer:** First I jotted down the basics and convert them to scientific
notation for easy calculation `~1 *10^3 bytes/request (1 KB)`

, ```
9 * 10^4
seconds/day
```

, and `10^5 requests/second`

. Then multiplied these numbers into
storage per day: ```
10^3 bytes/request * 9 * 10^4 seconds/day * 10^5
requests/second = 9 * 10^12 bytes/day = 9 Tb/day
```

. Then we need to use the
monthly cost for disk storage from
sirupsen/napkin-math (or your cloud's
pricing calculator) -- `$0.01 GB/month`

. So we have `9 Tb/day * $0.01 GB/month`

. We
do some unit conversions (you could do this by hand to practise, or on
Wolframalpha) and get to `$3 * 10^3 per month`

, or $3,000 per month. Most of
those who replied got somewhere between $1,000 and $10,000 -- well within an
order of magnitude!